6:2(1+2)
6:2(1+2). 1+2'yi istediğiniz gibi yazabilirsiniz, sonuç değişmez. O halde soldan başlayarak sırasıyla işlemleri tek tek yaparız. With no additional information, i'd assume the author intended strictly left to right: Now i'm in college and i can tell you it is definitely not 1. Şimdi görüyoruz ki bu işlemde artık çarpma ve bölme işlemleri kalmış durumda.
This is the way it would resolve if you typed it into google the correct answer is 9. tex6 \,\colon 2 \cdot (1+2)=6 \,\colon 2 \cdot 3=3 \cdot 3=9./tex. 1+2'yi istediğiniz gibi yazabilirsiniz, sonuç değişmez. But let us see what this question really implies. Someone please end this idiotic facebook debate, preferably a college algebra professor.
Daha doğrusu, önce çarpmalı mıyız, bölmeli miyiz? O halde soldan başlayarak sırasıyla işlemleri tek tek yaparız. This is the way it would resolve if you typed it into google the correct answer is 9. 2 (3) does not say 2×3 and to most of us both these aforementioned expr. Parantez içindeki toplama işleminde de bir sorun yok.
But let us see what this question really implies.
tex6 \,\colon 2 \cdot (1+2)=6 \,\colon 2 \cdot 3=3 \cdot 3=9./tex. But let us see what this question really implies. Many say, this should be solved according to bodmas so the answer will be 9. The problem as it is written is 6÷2(1+2) , the ÷ cannot be substituted with a fraction bar because they have different ranks on the order of operations. The question is whether the answer to the equation 6/2(1+2)=x is 9 or 1.
Parantez içindeki toplamayı yapıp sonra onu çarpacağımız da belli. 2 (3) does not say 2×3 and to most of us both these aforementioned expr. 1+2'yi istediğiniz gibi yazabilirsiniz, sonuç değişmez. Many say, this should be solved according to bodmas so the answer will be 9. tex6 \,\colon 2 \cdot (1+2)=6 \,\colon 2 \cdot 3=3 \cdot 3=9./tex.
A bc − d ef = b + a ⋅ cc − e + d ⋅ ff. The problem as it is written is 6÷2(1+2) , the ÷ cannot be substituted with a fraction bar because they have different ranks on the order of operations. Sorun, işlemlerin hangi sırayla yapılacak olmasında. Now i'm in college and i can tell you it is definitely not 1. You do the addition first to get 6 / 2 x 3, then you must do order of operations from here in the order that they are presented in.
I try to explain it to all these people.
Parantez içindeki toplamayı yapıp sonra onu çarpacağımız da belli. Now i'm in college and i can tell you it is definitely not 1. But let us see what this question really implies. Sorun, işlemlerin hangi sırayla yapılacak olmasında. 1+2'yi istediğiniz gibi yazabilirsiniz, sonuç değişmez.
This is the way it would resolve if you typed it into google the correct answer is 9. 2 (3) does not say 2×3 and to most of us both these aforementioned expr. The question is whether the answer to the equation 6/2(1+2)=x is 9 or 1. With no additional information, i'd assume the author intended strictly left to right: But let us see what this question really implies.
A bc − d ef = b + a ⋅ cc − e + d ⋅ ff. But let us see what this question really implies. The problem as it is written is 6÷2(1+2) , the ÷ cannot be substituted with a fraction bar because they have different ranks on the order of operations. This is the way it would resolve if you typed it into google the correct answer is 9. O halde soldan başlayarak sırasıyla işlemleri tek tek yaparız.
You do the addition first to get 6 / 2 x 3, then you must do order of operations from here in the order that they are presented in.
Parantez içindeki toplama işleminde de bir sorun yok. Bu soruda işlem önceliğinde ilk olarak parantez içindeki işlemi yaparız. Someone please end this idiotic facebook debate, preferably a college algebra professor. Daha doğrusu, önce çarpmalı mıyız, bölmeli miyiz? This is the way it would resolve if you typed it into google the correct answer is 9.
Posting Komentar untuk "6:2(1+2)"